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To: badgerlandjim
Rossi shows his computations for the 517 tons of oil equivalency in [0074] thru [0087] in Table 1 of the patent application. All the computations seem to be there. Somebody with better math skills than mine will have to verify or reject the accuracy.

In my calculation in #136 and #142, I got 7.9E11 (E = shorthand for "times 10 to the") joules. Rossi arrives at [0086] with 9.63E11 joules per 59 gram mole (probably because he uses 10 MeV per atom, and I was going with 8.2 Mev based on his earlier article). This is 2.3E8 kcal.

The problem arrives in [0087].

According to DOE, a metric ton of oil is 7.3 barrels, 4.3E7 BTU, or 4.5E10 joules, or 1.1E7 kcal. A kg of oil is therefore 4.5E7 joules, = 11,000 kcal. Taking 9.6E11 joules / 4.5E10 joules/ton gives 21 tons/mole or 0.36 tons of oil per gram of nickel, not 30,000 tons.

159 posted on 05/25/2011 8:00:44 AM PDT by PapaBear3625 ("It is only when we've lost everything, that we are free to do anything" -- Fight Club)
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To: PapaBear3625
Thanks. I wonder if Rossie meant to use gallons instead of tons when he got to [0087]. That would pretty well tie you and Rossie together and allow for a mistake in translation.

It still seems like the hot fusion guys aren't working very hard to discredit Rossi if they haven't sent a team to Italy to check on that factory. Pretty negligent on the part of his critics if they haven't even read his latest patent app and discovered that address; or checked the data he has provided, like you have. Maybe they just want to cast aspersions without really investigating? Or maybe they don't want to discover a working factory being heated with the E-cat?

161 posted on 05/25/2011 8:32:45 AM PDT by badgerlandjim
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