So it's about on par with catch a bowling ball dropped from about 20 feet up.
The bowling ball weighs ~10lbs. THen the speed is:(from 1/2*m*v2
v = SQRT(60*2*32/10) = 20 ft/sec
The height is: from E= m*g*h: 60/10 = 6ft
or from : v = a*t: 20/32 = 0.61secs
THen from x = 1/2*a*t2: 0.5*32*0.61*0.61 = 6.0ft.
A bowling ball from 6ft. That's easier to catch though, because of the surface area. It's still got a lot of momentum. A bowling ball from 20ft is 200 ft-lbs. That's more like a train...