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To: Centurion2000
"on par with catch a bowling ball dropped from about 20 feet up."

The bowling ball weighs ~10lbs. THen the speed is:(from 1/2*m*v2

v = SQRT(60*2*32/10) = 20 ft/sec

The height is: from E= m*g*h: 60/10 = 6ft

or from : v = a*t: 20/32 = 0.61secs
THen from x = 1/2*a*t2: 0.5*32*0.61*0.61 = 6.0ft.

A bowling ball from 6ft. That's easier to catch though, because of the surface area. It's still got a lot of momentum. A bowling ball from 20ft is 200 ft-lbs. That's more like a train...

80 posted on 10/15/2004 8:42:26 AM PDT by spunkets
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To: spunkets
A bowling ball from 20ft is 200 ft-lbs. That's more like a train...

Well, a 4 bore rifle spits about think.

Makes a 454 look like a popgun

82 posted on 10/15/2004 8:54:42 AM PDT by Centurion2000 (Truth, Justice and the Texan Way)
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To: spunkets
It's a little quicker to go directly from your 60 ft-lbs.

That is the energy is equal to the difference of potential equal to 60 ft-lbs.

60 / 15 = 4 ft.

60 / 10 = 6 ft.

100 posted on 10/15/2004 10:32:16 AM PDT by WildTurkey
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