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To: hobbes1
2 days? Well you beat us......we made one day of 7th grade...... now he's home with me .....we're back to home schooling........
33 posted on 09/04/2003 5:29:25 AM PDT by WhyisaTexasgirlinPA (Hey, it's me......remember me?)
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To: WhyisaTexasgirlinPA; Gabz; hobbes1; xsmommy; maxwell; Eala; Flurry; Cyber Liberty
Congrats!

You won't ever regret it .... I think. 8<)

(Thinking of Monday night at 12:30 working with Jean on her Physics 3302 problems: many mechanical, rotation inertia; sliding objects problems ...)

One funny problem I need to consult Eala, Maxie and Cyber need to think about: (Xsex can probably do it in her sleep ... so I won't ask her.)

Imagine an eskimo sitting on a prefectly round frictionaless(hemispherical) igloo at the north pole. A very tiny force starts moving him sideways: at what point does his bottom leave the igloo's surface?

Way I figgured it: ya gotta calculate the x,y,z vectors of his weight (forces down, out, and sideways) as a sin/cos function of his angular position starting from the top and going down all the to the extreme side point.

This gives you a vector of sideways acceleration AND downwards acceleration that changes with his radial position: so the "perfect" trajectory laws of motion (free fall in vacuum where there is NO horizontal acceleration and a constant downwards accelration don't apply)!

Assume there is no igloo in the way, and calc the trajectory for his path using the changing horizontal acceleration to get (x,t) and the changing (vertical) acceleration to get (y,t): plot the curve.

Plot a second curve of a quarter circle.

find the intersection of the two - this is where his modified" parabolic trajectory leaves the surface of the igloo.

Sound right? (Jean doesn't think so...)
168 posted on 09/04/2003 10:15:12 AM PDT by Robert A Cook PE (I can only support FR by donating monthly, but ABBCNNBCBS continue to lie every day!)
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