Several replications of a methodology to generate an ultra dense form either of protium or deuterium have been conducted. The conclusion drawn from experiments upon the material is that a particle spacing of approximately 52 femtometer is induced by a phase change from a less dense state, when prompted by a disturbance (laser, beta ray, even fluorescent lighting.) This lattice like spacing is within proximity for nucleons to tunnel—and associated fusion reaction products are detected with deuterium usage.
In addition, the generation of mesons, different flavors of which are generated based on protium or deuterium experiments, is a serendipitous discovery. Protium yields a decay chain resultant of negative muons, which act as 200 times more massive electrons, capable of also achieving the 52 fm spacing of nucleons and yield a fusion reaction. The energy invested to generate these muons is much less than prior methodology. Serious investment to develop a commercial muon driven fusion process is ongoing. Their first product is likely to be a testing article based upon the generation of neutrons in a field setting.
Over the prior two years, the focus shifted to direct applications for the meson decay-chain products. About 54% of all energy is spirited away by neutrinos, leaving the possibility of tapping a relativistic flow of charged particles for direct conversion to electricity. The particle flux in the small lab experiments is sufficient to directly drive an oscilloscope.
Sounds familiar.
Mesons from Laser-Induced Processes in Ultra-Dense Hydrogen H(0)
Leif Holmlid
Published: January 12, 2017
https://doi.org/10.1371/journal.pone.0169895
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There is some discussion regarding the applicability of this paper over here
Posted by ko’malley on 11 Jun 2017 at 22:23 GMT
http://www.e-catworld.com...
Alan DeAngelis • a day ago [hush][hide comment]
Study the simplest system. Less Chase’s “football” was just deuterium gas and palladium on carbon. The creation of helium-4 was seen by mass spectroscopy (at 36:35 min. in video).
My two cents: the pairs of electrons, ~, in the palladium deuteride bonds, D~Pd~D, lower the coulomb barrier allowing palladium to absorb two deuterons when heated (heat = infrared stretching of the covalent deuteride bonds) to form cadmium in an excited state, Cd*, which in turn fissions back into palladium, Pd, and helium-4, He. Therefore, a fusion-fission reaction with 24 MeV of kinetic energy without a gamma ray.
D~Pd~D > Cd* > Pd + He + 24 MeV of kinetic energy (with no gamma ray)
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Alan DeAngelis Alan DeAngelis • an hour ago
PS
Think about the Mitsubishi transmutations. Pairs of deuterons are reacting with metals.
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Kevmo Alan DeAngelis • 14 hours ago
Then how do you explain the Hydrogen-Nickel interaction?
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Alan DeAngelis Kevmo • 6 hours ago
H~Ni(64)~H > Zn((66)* > Ni(62) + He(4) 11.8 MeV (no gamma rays)
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Kevmo Alan DeAngelis • 3 hours ago
From what I have read there isn’t nearly enough Ni(62) nor He(4) found in these cells to account for so much long term heat.
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Alan DeAngelis Kevmo • 2 hours ago
I really don’t know. At the time, I was just thinking about the disappearance of Ni(64).
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Axil Axil Kevmo • 2 hours ago
Most energy produced by LENR goes into the creation of muons and electrons. This energy comes from the decay of protons and neutrons. See my post above for an explanation of how this happens.
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Kevmo Axil Axil • an hour ago
Is there an experiment that would verify your hypothesis?
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