If I remember correctly, when a hydrocarbon is burned (oxidized), MORE molecules of water (H2O) are generated than molecules of CO2. For example:
Methane = CH4: CH4 + 3 O2 => 2 H2O + CO2
Ethane = C2H6: C2H6 + 5 O2 => 3 H20 + 2 CO2
Propane = C3H8: C3H8 + 7 O2 => 4 H2O + 3 CO2
It appears that no one at the AP understands that...
And they actually use less oxygen!
CH4 + 2 O2 = 2 H2O + CO2
2 C2H6 + 7 O2 = 6 H2O + 4 CO2
C3H8 + 5 O2 = 4 H2O + 3 CO2