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To: Heartlander

They did not mention how the rotations were counted. If it is based upon the pulse rate of the laser while circular, it would seem that the rotation is limited to the lasers ability to pulse.


6 posted on 07/26/2018 11:49:07 AM PDT by rjsimmon (The Tree of Liberty Thirsts)
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To: rjsimmon
Not necessarily.

Think of a strobe. Perhaps it's only catching it synchronously.

Say it's going twice as fast, you're only seeing it once for every two rotations.

16 posted on 07/26/2018 12:02:55 PM PDT by Calvin Locke
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To: rjsimmon

Interesting point.

It’s a vacuum. Can’t you just apply acceleration to it and multiply by the amount of time applied to get velocity at the instant the acceleration is removed? It’s going to be a linear function, if I recall my physics.

Kinda like pushing on a merry go round that’s frictionless. As long as you can apply force, the merry go round accelerates?

I’ll just wait for the schooling now . . .


26 posted on 07/26/2018 12:11:32 PM PDT by RinaseaofDs
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To: rjsimmon
They did not mention how the rotations were counted. If it is based upon the pulse rate of the laser while circular, it would seem that the rotation is limited to the lasers ability to pulse.

The speed of light? Interesting. In a suspended vacuum, assuming the particle can maintain its integrity, if the pulse stop penetrating the spinning "device", have we not accelerated an object to the speed of light? WHOA!

What prevents the particle from spinning faster than light, besides light itself? Theoretically, if the device is spinning at the speed of light and then launched in space, is there not a component of the device (the outer edge) that will exceed the speed limit?

Physics is fun. ;o)

40 posted on 07/26/2018 12:27:48 PM PDT by Tenacious 1
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To: rjsimmon

Maybe measuring an electrical field created by lots of electrons moving around and around and around...


78 posted on 07/26/2018 3:47:44 PM PDT by 1FreeAmerican
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