Mother is left stumped by her seven-year-old daughter's maths homework question (but could...

DAILY MAIL UK ^ | Jan 31, 2018 | Alex Matthews For Mailonline

[wardaddy]

Btw

Mom is right

Question requires a half a dog

Mistake on lesson writers not mom

[Daffynition]

[publius911]

Looks like nobody can come up with the expected answer, without accepting a fractional dog to play a role.
So the solution must be an error in formulating the question.

[LukeL]

That is what the problem was suppose to say, but the problem said 36 MORE small dogs than large dogs. Your way there are only 23 more small dogs than large dogs.

[abigkahuna]

Reminds me of Egyptian Mathematics. Without using algebra, or X such as which is used in modern day mathematics:

A quanity with ¼ added to it becomes 15.

This simple question took mathmaticians years to figure out how the Egyptians solved this simple problem on the Ahmes Papyrus. The answer is as follows:

[Assume 4.] [That is] multiply 4, making 1/4, namely 1, [so that the] Total is 5 [proceeding in the usual manner:
\1 4 \l/4 1
Total: 5].

[As many times as 5 must be multiplied to make 15, so many times 4 must be multiplied to give the required number.]

Operate on 5 to find 15 \1 5
\2 10 Total: 3.
Multiply 3 tunes 4. 13 26
\4 12
This becomes 12. [And find its 1/4:]
1 12 \l/4 3
Total: IS.
[Hence] the quantity is 12 and its 1/4 is 3 and the total b IS.
[This checks out since the sum agrees with what was originally specified.]

[LibWhacker]

42 small dogs
6 big dogs
1 chili dog

[Axenolith]

You know what’s funny, is I “get” that totally looking at your breakdown, particularly at the check your work part, but the logical inconsistency created by “dogs” as a set ending with a fractional algebraic answer seems to screw with the mind.

[Axenolith]

DOH!

I’m going to have to leave this with wife before I sleep... muahahaha...

[unlearner]

“the logical inconsistency created by ‘dogs’ as a set ending with a fractional algebraic answer seems to screw with the mind”

It is clear that the educators messed up here. The math is too sophisticated for most children of that age. Counting dogs in a show strongly implies whole numbers only.

Either something was left out, like number of medium dogs, or they simply should have left out the “more... than” and pegged the small dog count at 36, and said to solve for the large dog count. Simple age-appropriate subtraction.

[Nifster]

I don’t understand the teachers answer at all. You can’t have a half a dog. The answer to the question is 36. There are 36 small dogs and 13 large

[Nifster]

Yup

[SnuffaBolshevik]

"I don’t understand the teachers answer at all. You can’t have a half a dog."

Have you ever been to a Korean restaurant? ;)

[mylife]

Bonus question: “therefore, how many pancakes does it take to shingle a dog house?”

[RoosterRedux]

Bfl

[scrabblehack]

Hmmm....it must be that
l = [0,6]
s = [36,42] then
m = [1,13].
That is, there are somewhere between 0 and 6 large dogs,
36 and 42 small dogs, and 1 and 13 medium dogs.

For that matter,
http://www.trainpetdog.com/dog-breed-size-chart.html
has giant and very large dogs as well. So it could be between 1 and 13 medium/very large/giant dogs.

[Osage Orange]

Dog is God backwards...............

[867V309]

One should never enter 1/2 of a dog into a dog show.

well, if it shows well, it's probably a winner.

but seriously, X + (X+36)=49 or large dogs+(large dogs+36)=49     that's wrong

it should be (X+36)=49 or (Xlarge dogs+36small dogs)=49

So X= large dogs = 49-36=13.   

How many small dogs are signed up to compete?:

49(all dogs)-13(large dogs)=36(small dogs.)

[867V309]

sorry, misread the problem...

[nickedknack]

LaQueesha is meeting Tyrone at the movies at 7pm. It’s 6:25pm, and Tyrone is 5 miles away.

Q: Who is Tyrone’s biological father?

[spintreebob]

if you chop a large dog in half does it then become a small.dog?!

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