You mixed Farenheit with Celsius in your calculation of the temperature change. If you use consistent units, the change is lower (i.e., if you use Kelvin/Celsius, you don’t have 49 and 72— you have (17*5/9) for the 49, and 40*5/9 for the 72. THat is 49 degrees F is (0 +(49-32)*5/9) in the other scale.
“You mixed Farenheit with Celsius in your calculation of the temperature change. If you use consistent units, the change is lower (i.e., if you use Kelvin/Celsius, you don’t have 49 and 72— you have (17*5/9) for the 49, and 40*5/9 for the 72. THat is 49 degrees F is (0 +(49-32)*5/9) in the other scale. “
Noted in 196. Acknowledged in 200. Actually the formula uses Kevin, not Celsius.
For 49 F you would have K = 5/9 * (F-32) + 273 (approximately).