[Kevmo]

The Cold Fusion/LENR Ping List

http://www.freerepublic.com/tag/coldfusion/index?tab=articles

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http://lenr-canr.org/

[Kevmo]

Interesting discussion on Vortex regarding this

http://www.mail-archive.com/vortex-l@eskimo.com/msg81294.html


On Mon, May 27, 2013 at 10:03 AM, Edmund Storms wrote:
> That is the idea. However, why would only a few hydrons fuse leaving just
> enough unreacted hydrons available to carry all the energy without it
> producing energetic radiation? I would expect occasionally, many hydrons
> would fuse leaving too few unreacted hydrons so that the dissipated energy
> would have to be very energetic and easily detected
>
***That would account for the very occasional neutron being observed,
right? And it also would account for how few of them get observed as
well. They only happen when a multiple-fusion event takes place inside the
BEC and there isn't enough BEC infrastructure to absorb the energy.



> . Also, how is this mass-energy coupled to the unreacted hydrons? The BEC
> is not stable at high temperatures, which would be present inside the BEC
> when mass-energy was released. I would expect this release would destroy
> the BEC, leaving the fused hydrons to dissipate energy by the normal hot
> fusion method.
>
***I would expect it as well. Like an explosion taking place inside a
house, the structure blocks much of the energy while it is momentarily in
place. And then another BEC forms, 2 atoms fuse, and the reaction goes on
& on.




> The concept appears to have many logical flaws.
>
> Ed Storms
>
> On May 27, 2013, at 10:08 AM, Kevin O'Malley wrote:
>
> Then is that an explanation of why Gamma rays are not observed in LENR?
> If 2 of the atoms inside a multi-atom BEC fuse together, the incoming
> radiation (to the rest of the BEC) gets subdivided based upon how many
> atoms have formed the BEC. Right?
>
>
> On Mon, May 27, 2013 at 12:49 AM, Axil Axil wrote:
>
>> This paper verifies that a photon eradiated Bose-Einstein condensate
>> will cut the frequency of incoming photons by dividing that frequency
>> between N numbers of atoms.
>>
>>
>> http://arxiv.org/pdf/1203.1261v1.pdf
>>
>>
>> Rydberg excitation of a Bose-Einstein condensate
>>
>>
>> “The results of theoretical simulations are represented by the
>> continuous lines.
>>
>>
>> According to the super-atom picture the collective Rabi frequency for the
>> coherent excitation of N atoms is
>>
>>
>> frequency (collective) = square root(number of atoms) X
>> frequency(single);
>>
>>
>> Where the single-particle Rabi frequency (single) is app 2 pi x 200 kHz
>> for our experimental parameters.”
>>
>
>

[Migraine]

hope levity is not too out of place — but the Beach Boys already accomplished this:

“I’m picking up good vibrations;
She’s giving me excitations...”

Hope this helps.

Otherwise, I just read some things that are distinctly over my head. :)