No.
Although I don’t know the rate of electrical resistence and I don’t need to to teach a principle, but bear with me.
But let’s say that the first 200 watts are awash, as it is used to overcome the electrical resistence.
That would leave the net wattage, to be used for power for the uninducted lighting at 800 watts and 100 watts for the inducted lighting.
In this case, if it were the case, it would mean a savings of 87.5 percent, once you account for the electricity being used just to overcome the initial electrical resistence.
Nope. Doesn’t matter where the power goes.
All the generator that powers the light cares about is that with one, it has to provide 1000 watts, with the other it only has to provide 300 watts.
A 70% reduction.