[Sherman Logan]

Only need to overcome friction loss.

I don't think so. That would be for horizontal movement.

There is a specific energy requirement, in addition to frictional losses, to raise a pound of anything a foot above its starting point.

In fact, I think it's a unit of measurement called a foot-pound. :)

[PapaBear3625]

There is a specific energy requirement, in addition to frictional losses, to raise a pound of anything a foot above its starting point.

Unless they have the water in a loop, in which case the weight of the water in the down-going side of the loop balances the water in the upcoming side, leaving only frictional losses in the round trip.

[PSYCHO-FREEP]

That's correct. Use the Hydrostatic Pressure formula of;

HP = wt. per gallon (water @ 8.3 ppg) x depth x.052 = Hydrostatic Pressure.

At 5300 feet vertical, the bottom hole pressure (hydrostatic) is 2287 psi. One would need to maintain a pump pressure exceeding that pressure to move a column of fluid at that depth. Velocity also increases circulation density which also requires more power to maintain the flow of the fluid column. It also varies due to the rheology of the fluid used. (Viscosity/yield point)

[loungitude]

You are correct. I assumed that water was sent from the surface, heated, and returned to the surface. Since the water is already down there, then yes it must be lifted up as you said.