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To: Catphish

er, square root of 8!


15 posted on 10/28/2010 10:28:12 AM PDT by Catphish
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To: Catphish

youre right but actually y can be less than or equal to -sqrt 8, greater than or equal to sqrt 8, and 0 for x=isqrt2


19 posted on 10/28/2010 10:35:16 AM PDT by hannibaal
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