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To: tacticalogic
“Okay, I'm confused. In a geocentric model I wouldn't think there would be any Earth rotation speed.”
Hmm, my bad.
Should be:

transit time in seconds = distance in meters ÷ speed of light in meters per second
displacement in degrees = Sun angular orbit speed in degrees per second × transit time in seconds

Angular orbit speed would be 360°/24 hours, or 0.00416°/second.

The math is the same, just a different name.

“I'm still not getting that to fit the model conceptually. This isn't a matter of orbiting the sun, but rotating in place at more or less a fixed distance from the sun.” [#1143]
I gave the heliocentric and geocentric models side by side.

If you're only interested in the geocentric model, you can ignore the stuff referencing the heliocentric model.
1,154 posted on 02/03/2009 6:42:57 PM PST by Fichori (https://secure.freerepublic.com/donate <= Donate and show Obama how much you love him)
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To: Fichori
If you're only interested in the geocentric model, you can ignore the stuff referencing the heliocentric model.

Comparing either one to an object rotating in place relative to the other seems an apples-to-oranges arrangement.

1,156 posted on 02/03/2009 6:53:15 PM PST by tacticalogic ("Oh bother!" said Pooh, as he chambered his last round.)
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