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To: burzum
Ummmmm ... no.

Whatever mass you're kicking out of the back of the vehicle is accelerated relative to the vehicle. No matter how fast the vehicle is going, if the mass-flow-rate and the delta-v is the same, the thrust produced is the same and the energy cost is the same.

49 posted on 09/10/2007 7:13:29 PM PDT by DuncanWaring (The Lord uses the good ones; the bad ones use the Lord.)
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To: DuncanWaring

You do not conserve energy in your case. KE = 1/2 mv². The higher the velocity, the higher the cost per incremental change in velocity. Since, P = F * v, your rocket would become much more powerful the faster it goes if it had a constant force. Does it make sense to you that an object that hasn’t changed its mass becomes more powerful the faster it goes when it is only powered by a constant power source?


53 posted on 09/10/2007 7:31:58 PM PDT by burzum (None shall see me, though my battlecry may give me away -Minsc)
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To: DuncanWaring

Oh, and before you mention it, an accelerating body is, by definition, not in an inertial reference frame. So your Galilean transformation arguments do not apply.


54 posted on 09/10/2007 7:36:27 PM PDT by burzum (None shall see me, though my battlecry may give me away -Minsc)
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