To: RadioAstronomer
As I recall, you get a “bonus” of 1 MeV when you go from odd to even numbers of nucleons in the neutron capture event. The binding energy gets you about 5 MeV, the “bonus” of 1 MeV going from odd to even gets you one more, for a total of 6 MeV, just the amount you need to add to the nucleus to induce the fission reaction. U238 neutron capture goes from even to odd, so you don’t get the bonus. The 5 MeV you get from the binding energy isn’t enough to do it for thermal neutron-induced fission. You need an incoming “fast” neutron (1 MeV or more) to fission the U238 nucleus. So it is a threshold reaction rather than a thermal neutron capture. Do I have the numbers right (it’s been awhile)?
80 posted on
04/12/2007 1:19:11 PM PDT by
chimera
To: chimera
As I recall, you get a bonus of 1 MeV when you go from odd to even numbers of nucleons in the neutron capture event. The binding energy gets you about 5 MeV, the bonus of 1 MeV going from odd to even gets you one more, for a total of 6 MeV, just the amount you need to add to the nucleus to induce the fission reaction. U238 neutron capture goes from even to odd, so you dont get the bonus. The 5 MeV you get from the binding energy isnt enough to do it for thermal neutron-induced fission. You need an incoming fast neutron (1 MeV or more) to fission the U238 nucleus. So it is a threshold reaction rather than a thermal neutron capture. Do I have the numbers right (its been awhile)Please, don't even think about a trip to Iran any time soon.
To: chimera
82 posted on
04/12/2007 8:35:27 PM PDT by
RadioAstronomer
(Senior and Founding Member of Darwin Central)
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