Another question.Forgetting that there has to be some males in the population,taking the 24,000 number at 5 births per 10 year lifespan what is the population growth.
Taking the stated constant of 24,000 living for 10 years every year 10% of the population die equaling 2,400 animals.Of the remaining 21,600 half are not reproducing leaving just shy of 11,000 new births/year.
It would seem the birth/lifespan/death rates to maintain a population of 24,000 are much to high.
Of course in reality some of the births,which should over time be about 50%,would be males which would half the numbers and make the equations more plausible.
Corrections requested if I have calculated incorrectly.
Of course in reality some of the births,which should over time be about 50%,would be males which would half the numbers and make the equations more plausible. Standard practice when calculating birth rates is to specify it for some number of unsexed individuals; depending upon the male/female ratio, the female birthrate will be about twice that of the population as a whole while the male birthrate will be zero. If, within the antelopes, males and females are represented in equal numbers at all life stages, each female will give birth to an antelope per year, of which half will be males. Or an average of one female every two years.