Posted on 01/06/2017 8:51:18 PM PST by logi_cal869
Thanks in advance.
The chair is against the wall.
The answer is 7 :)
My doc says radiation is cumulative.
Check these out. You can probably google NORM/TENORM Faq sheets too.
http://www.easysurf.cc/cnver24.htm
http://www.iem-inc.com/information/radioactivity-basics/basic-concepts
so is this a question about “new born Potassium-40” or the use as you will, as an alternative to radio carbon dating? it matters in terms of how the community looks at radioactivity.
Many years ago, I was doing a research project that involved the force of sliding friction between a certain two materials in contact. So I went to various sources to look for the accepted data.
I was surprised to see how much the data varied on the exact same two materials. I suspect that was due to each researcher’s estimate of uncertainty. Different estimates of uncertainty would lead to different results. Perhaps that is what you are facing here.
The lower number you are seeing may well be the specific activity of naturally occurring potassium which would only contain a small fraction of K-40.
William tell gave you the answer. The much lower figure is the amount of radiation from k40 in “natural K”. K40 is only a tiny part of natural K.
The higher figure is for pure k40
Now you know why mechanical and civil engineers design everything 5X what good enough "should" be.
Thank God electronics are more exact.
This may help you too.
http://www.calrecycle.ca.gov/LEA/Conference/06Conf/Presentation/Day2/Radioactive/Greger/K40Food.pdf
Sorry. That information is need to know. ;)
“Take 818 pCi/g and divide by 0.00012 and you get 6.8 uCi/gram of K-40, which is pretty close to the 7.1 uCi/g you already had...”
The 854 is about 7.1.
Thanks, but that actually references the ANL fact sheet, the crux of the problem.
Thanks, but that and your other link are both sources I alluded to utilizing the noted figures, both without reference.
I think I understand what you’re trying to demonstrate. Yes, the math is academic.
However, if Potassium-40 is 0.012% of ‘naturally-occurring potassium’ - and only Potassium-40 is radioactive - then the 0.0000071 figure is nonsensical, suggesting that ALL natural potassium is radioactive.
The conclusion I came to is that an intern building the fact sheet made a boneheaded math error and represented the total possible radioactivity for 100% of naturally-occurring potassium, rather than the 0.012% figure, which in reality only represents the elemental breakdown, not the percentage of radioactivity.
Either I found an error, or the facts are escaping me still and I’m stuck in a boneheaded brainfart.
This is why I asked for help: I need other source(s) for data for which I’ve been unsuccessful or validation of my conclusion, that the 818 pCi/g figure is correct and that ANL, frankly, goofed.
In fact, the National Research Council source predates the ANL fact sheet by 6 years, published 1999....
...which just happens to state it matter-of-factly as such:
Potassium-40 is present at 0.0117% by mass in natural potassium, thereby imparting a specific activity of about 30 kBq/kb (800 pCi/g) of potassium.
I can accept a discrepancy of 0.0117% vs. 0.012%, but not 0.0000017 vs. 0.000000000818...
Disclaimer: Opinions posted on Free Republic are those of the individual posters and do not necessarily represent the opinion of Free Republic or its management. All materials posted herein are protected by copyright law and the exemption for fair use of copyrighted works.