However, once that first door is opened, my chance of picking the correct door (either remain with mine, or choosing a new one) is now 1 to @-1. This continues until we get down to the last two doors - mine and an unknown. Regardless of how many doors Monty has opened - my chance of choosing the correct door (either the one I have, or the one offered) is 1 in 2.
So, I agree that, before Monty starts opening his doors, my chance of having picked the correct on, is 1-@. I also agree that, once the game is over, my chance of having picked it right, from the beginning is 1-@. However, my chance, on the final decision (stay with Door #1, or take Curtain #3) is 1 in 2.
This is not that different than the old coin toss question ...
Or maybe I'm still missing a key piece of the puzzle?
I'm being honest - if I'm missing something I'd like to understand it!
You are hung up on the idea that the odds for a choice already made change upon learning more information. What’s done is done. Suppose you pick an apple from a barrel of apples and that apple has a worm in it. Does that worm go away because you are now given the choice of much more reliable apples?