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To: nickcarraway

PV=nRT ?


2 posted on 02/18/2025 5:11:55 PM PST by posterchild
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To: posterchild

Nope.


5 posted on 02/18/2025 5:15:06 PM PST by TexasGator (/1)
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To: posterchild

PV=nRT 8s the Ideal Gas Law.

It does not apply to solutions.


10 posted on 02/18/2025 5:28:09 PM PST by TexasGator (/1)
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To: posterchild

That is involved, but this is for two phase two component (H2O , CO2) system at two different temperatures. So it depends on the components esp water being polar.

Better start from here:
https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Equilibria/Solubilty/Temperature_Effects_on_the_Solubility_of_Gases#:~:text=The%20solubility%20of%20gases%20in,Equation%204%20to%20the%20left.


16 posted on 02/18/2025 5:32:06 PM PST by takebackaustin
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To: posterchild

That’s it.


22 posted on 02/18/2025 7:28:22 PM PST by mfish13 (Elections have Consequences.)
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To: posterchild

PV=nRT ?

Correct. I like [P = ρRT]. Fun with the equation of state:

So, we have the 1st law of thermodynamics,
[dQ = Cp(dT) - dP/ρ],
and, the equation of state, [P = ρRT].

Now, ρ = P/RT, substitute into 1st law of thermodynamics.

dQ = Cp(dT) - RTdP/P.

Set dQ = 0, no change in internal heat from condensation.

Now, Cp(dT) - RT(dP/P) = 0.
Or, Cp(dT/T) = R(dP/P). Integrate both sides,

Cp∫(dT/T) = R∫(dP/P). After integration,
(Cp/R) ln(T) limit: |To-θ = ln(P) limit: |Po-P(1013).

Now, ρ = P/RT, and dP/dz = -ρg (hydrostatic equation).
dP/dz = -Pg/RT, hold temperature T constant.
dP/P = -g(dz)/RT, integrate,
ln(P0/P1) = -gz/RT, exponentiate both sides,
P0 = P1•exp(-gz/RT).


29 posted on 02/18/2025 7:48:53 PM PST by thepoodlebites (and that government of the people, by the people, for the people, shall not perish from the earth.)
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To: posterchild

Shocker! Coca cola, set out in the sun, foams in your mouth!

Does nobody work in the heat anymore?


32 posted on 02/18/2025 10:58:43 PM PST by If You Want It Fixed - Fix It
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