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To: hardspunned

Since you mention it as kinetic, how much mass is involved? It would have to be a large mass to do any damage. And this limits it to only the most powerful rockets?


7 posted on 11/26/2024 6:27:58 AM PST by caver ( )
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To: caver

would have to be a large mass to do any damage
——————
I suggest you study the massive underground weapons facility in Dnipro that was totally destroyed by Vlad’s Oreshnik missile attack. 1 mile by 1 1/2 miles- gone. Initial video and reports show total destruction, down to the three story underground manufacturing facilities. Gone.

Western MSM has been very, very quiet trying to downplay the weapon. The huge facility was assembling US / EU missiles, even repainting and relabeling western markings with Ukrainian markings…..oh what a web we weave when we practice to deceive….the number of eliminated western defense companies and Ukie workers is unknown at this time, but rumored to be in the hundreds.

Post war analysis will be stunning…..there is no wonder why NATO is holding an emergency meeting today.


26 posted on 11/26/2024 6:41:19 AM PST by delta7
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To: caver

It is not the mass, it is the velocity that makes kinetics formidible.

Kinetic Energy = 1/2 mass times velocity squared


30 posted on 11/26/2024 6:43:01 AM PST by The_Media_never_lie ( @whoisourPresident)
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To: caver

I think the point is that at Mach 10 the kinetic energy is elevated. I am not a physicist, but you can get the idea from a .22 slug which is also a kinetic weopon. If you toss it across the room is it pretty harmless. But at Mach 0.30 it will blow a hole in your skull. I am guessing that E= (MC)(MC) means something more serious that times 10.


53 posted on 11/26/2024 7:19:02 AM PST by anton
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