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To: BipolarBob

I don’t deny that his invention can achieve that speed. I do deny that, standing on it, he or anybody else, could either stay on it or control it. Long ago, in my younger years I had a BMW R74/5 motorcycle. If, without a fairing, I even got it up to 60 mph, it became very hard to control because of the terrific force of the wind. Same thing’s going to happen to him as he increases his speed. If you don’t believe me, just try standing outside in a hurricane and see what happens.


17 posted on 07/14/2019 2:13:25 PM PDT by libstripper
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To: libstripper

I’ve ridden a motorcycle to 105mph with no fairing no problem.


21 posted on 07/14/2019 2:16:53 PM PDT by 1FreeAmerican
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To: libstripper

“ I had a BMW R74/5 motorcycle. If, without a fairing, I even got it up to 60 mph, it became very hard to control because of the terrific force of the wind. “

Something else was going on. Lots of naked i.e. unfaired bikes go over 100 mph all the time with no control problems. Dirt bikes (with knobby tires!) have been to 120. My Buell (not me riding) 140 with only a tiny handlebar fairing.


24 posted on 07/14/2019 2:20:04 PM PDT by steve86 (Prophecies of Maelmhaedhoc O'Morgair (Latin form: Malachy))
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To: libstripper
in my younger years I had a BMW R74/5 motorcycle. If, without a fairing, I even got it up to 60 mph, it became very hard to control because of the terrific force of the wind.

You had issues that did not involve the wind. I have been way over 100 on naked bikes many times. Sometimes on the road, more often on a road racing circuit.

Never had the slightest control problem.

38 posted on 07/14/2019 2:54:35 PM PDT by doorgunner69
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To: libstripper

1CdA x 25.6psf x 7 sq ft= about 200 Pounds of wind load @ 100MPH?
Maybe he could go superman style?

Armed with pressure and drag data, you can find the wind load using the following formula: force = area x pressure x Cd. Using the example of a flat section of a structure, the area – or length x width – can be set to 1 square foot, resulting in a wind load of 1 x 25.6 x 2 = 51.2 psf for a 100-mph wind. A 10-foot–by–12-foot wall claims an area of 120 square feet, meaning that it would have to withstand a 100-mph wind load of 120 x 51.2 = 6,144 psf. In the real world, engineers use formulas that are more sophisticated and contain additional variables.
https://sciencing.com/calculate-wind-loads-wind-speeds-6104140.html

Frontal area is typically measured in metres squared. A typical cyclist presents a frontal area of 0.3 to 0.6 metres squared depending on position. Frontal areas of an average cyclist riding in different positions are as follows

Tops* 0.632
Hoods* 0.40
Drops* 0.32

Coefficient of drag
Person stood upright 1.0
https://www.cyclingpowerlab.com/CyclingAerodynamics.aspx


43 posted on 07/14/2019 3:14:08 PM PDT by DUMBGRUNT ("The enemy has overrun us. We are blowing up everything. Vive la France!"Dien Bien Phu last message.)
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