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To: 240B; 75thOVI; Adder; albertp; asgardshill; At the Window; bitt; blu; BradyLS; cajungirl; ...
Weekly digest ping, and to all on both lists (and all who read this topic), hope you have a great weekend.

24 posted on 02/28/2019 11:08:15 PM PST by SunkenCiv (and btw -- https://www.gofundme.com/for-rotator-cuff-repair-surgery)
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To: All

There’s an equation which relates the period of a planet to its distance from the Sun.

Period squared = distance cubed

(where distance is the average distance from the Sun).

For example, Jupiter has a period of 11.86 years, and an average distance from the Sun of 5.1 a.u. (astronomical units, the distance of earth from the Sun).

So 11.86 squared = 5.1 cubed.

For Neptune, it’s 165 (years) squared and 30 (a.u.) cubed.

This planet that is supposed to be ten times as far from the Sun as Neptune is 300 a.u. from the Sun. Cube that and you get 27,000,000. The square root of 27 million is about 5,200. So the period of this planet would be 5,200 years.


25 posted on 02/28/2019 11:36:13 PM PST by Peter ODonnell (Take the next train to Marxville and I'll meet you at the camp)
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