Posted on 07/04/2017 5:09:29 PM PDT by Extremely Extreme Extremist
Prayers for him and his family
ID is the abbreviation for Idaho, IN is the abbreviation for Indiana.
Wasn’t a falling bullet that isn’t possible. He was shot either intentionally or by a stray bullet intended for someone else.
Hey Pendejos, this is not Mexico
Wrong time of day to play— should have been in the midnight basketball league as per Clinton. Hope he does fine.
A falling bullet doing that much damage?
Ummm, too bad that once it loses its velocity it doesn’t come back when it falls and can’t do that much damage on the way down.
You know people die all the time from celebratory gunfire, right?
It happens frequently. Some years ago a bullet came though the window of my mom's third floor apartment. From the hole in the window and the impact of the bullet in the floor, it had arrived at around a 45 degree downwards trajectory.
or the Gaza Strip.
Sorry, it is indeed possible for a falling bullet to do critical/lethal damage.
Not if it’s truly a falling bullet and lost its inertia. At a bullets terminal velocity from falling it doesn’t have the energy. This has been tested numerous times. Now if the angle was much lower that’s a different story.
A bullet is falling from the instant it leaves the muzzle. With enough horizontal velocity, it can do damage.
I don’t know if anyone has done the math about how much force a falling bullet would be at.
We know after apogee it is just a freefalling weight and at some point hits terminal velocity. A penny hits terminal velocity at about 50 feet (lots of google results on “penny terminal velocity”).
A bullet masses about 10 g and falls at (9.8 m/sec)^2
50 feet is about 15 meters
so we have (someone check me)
(9.8^2)*15 =1440.6
1440.6 * 10 = 14,406 g of force = about 14 KG of force or about 6.5 pounds.
*OUCH*
If it hit point side down (unlikely) It could probably penetrate the skin and maybe ding the skull.
This seems consistent with answers to the old “will a penny dropped from the Empire State Building kill you>” question.
You brainy folk can check my math.
Note: Poor kid — hadda hurt.
I did the math in the following post: You can check me.
http://www.freerepublic.com/focus/chat/3566626/posts?page=15#15
It is possible for a bullet fired at an angle, into seemingly open air, to maintain significant velocity as it arcs downward. This wouldn’t be a shot straight up.
My shaky understanding is that if you managed to fire a bullet straight up into the air, then yes, the energy from the gunshot would bleed off and the bullet would come down at terminal velocity. But if the gun fires the bullet at an angle (almost certain) then the bullet will be coming in like a mortar round...or a bullet.
You left out terminal velocity.
I did the math at post 15 but you can check me.
>>My shaky understanding is that if you managed to fire a bullet straight up into the air, then yes, the energy from the gunshot would bleed off and the bullet would come down at terminal velocity. But if the gun fires the bullet at an angle (almost certain) then the bullet will be coming in like a mortar round...or a bullet.<<
Only at a very low angle. Assuming people shoot almost straight up it is close enough to “straight” to start to lose energy at apogee.
Too bad Mythbusters closed shop — it would be a great one to test at different angles.
I suppose it could be modeled if my physics was better.
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