The tidal force of a nearby object is proportional to the inverse CUBE of its distance times the mass of the object. This happens to be the density of the object times the cube of the ratio of its diameter to its distance.
But the apparent diameter in the sky of this object is simply the ratio of its diameter to its distance, so the tidal force is proportional to its density times the cube of its apparent diameter.
( This is my own observation, BTW. )
Thus, since the sun and moon have about the same apparent diameter ( nearly exactly, in fact ) the lesser tidal force of the sun is a demonstration of its lesser ( average ) density.
Also, with the density of the other planets being the same or somewhat less than the moon, it follows that their tidal influence is limited by the cube of their apparent diameters, making this influence in each case very much less than the tidal influence of the moon or sun. You do the math!
I can do the math.
I have the density part down to a tee.