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To: lepton
Every QB who was tested on the issue could immediately tell if a football was over or underinflated.

Those other QB's would have known that the footballs were underinflated as would any QB!

So the notion that Brady was playing with an underinflated football but the Colt QB had a normal inflated one and both were in the same weather conditions is simply too much!

You Patriot fans can convince yourselves of that nonsense.

81 posted on 07/16/2016 10:30:22 AM PDT by fortheDeclaration (Pr 14:34 Righteousness exalteth a nation:but sin is a reproach to any people)
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To: fortheDeclaration

There’s nearly a century of NFL QBs playing with underinflated footballs multiple times a season. Nobody noticed, nor cared.

The difference you are seeing, is when the pressure is different by 2 PSI in room temperature footballs, when the QBs have a chance to stand and knead the clean dry footballs with another football for immediate comparison - something they don’t do during the games.

Every one of those QBs who claimed they could tell each played games where the footballs were down by at least as much pressure as the lowest-pressure football in the 2014 AFCCG - with Mark Brunell in particular playing the equivalent of nearly a full season of such games, despite playing in Jacksonville in a southern division.

Most prominent QBs played games where the footballs were over 3 PSI low, and didn’t notice. And this is without the additional effects of rain. This is a normal phenomenon.


90 posted on 07/18/2016 7:49:38 PM PDT by lepton ("It is useless to attempt to reason a man out of a thing he was never reasoned into"--Jonathan Swift)
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To: fortheDeclaration

Oh...and even after being allowed to sit and warm up for 15 minutes, the three measured Colts balls were still underinflated, albeit no longer by as much. Had they not, they’d have to be magic.

Again, do the math using the equation in the Wells report. It’s not controversial, and hasn’t been for centuries. It’s one of those foundational discoveries that the latter half of the industrial revolution relied on.

Start with 12.5 PSI at 71 to 74 F, as the refs locker room was determined to be, and then for example calculate what the ball pressure would be in the Minnesota game last year at -6 F.

The formula for PSI and Fahrenheit is:
P2 =((P1+14.7)*(T2+459.67)/(T1+459.67)-14.7)

It’s not hard. Junior high school kids do it daily.


91 posted on 07/18/2016 8:02:31 PM PDT by lepton ("It is useless to attempt to reason a man out of a thing he was never reasoned into"--Jonathan Swift)
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