So... 1 Light year is 186,000 [mi]/[sec] x 31,536,000 [sec]=5,865,696,000,000 [mi].
The object has travelled a relative distance of 19.2 light years since passing:
19.2 x 5,865,696,000,000 [mi] = 112,621,363,200,000 [mi].
It was 70,000 year since it passed:
70,000 [yr] x 31,536,000 [sec]/[yr] x 1/60 [min]/[sec] x 1/60 [hr]/[min] = 613,200,000 [hr]
Velocity=Distance/Time:
112,621,363,200,000 [mi] / 613,200,000 [hr]=183,661 MPH.
You are right... I ran it 2x before on my phone and got the same (wrong) number... divided by 60 once too many times both times apparently. I was mostly interested what the orbital velocity of the system is... as in, are this thing and the sun in orbit around each other? Is it returning? I then just shrugged it off because I will probably be hit by a bus crossing the street tomorrow anyways.
Nope, never returning. It’s far, far above solar escape velocity at that distance. Here’s a color visible+infrared picture of the star I took last weekend though:
http://h.dropcanvas.com/vrq2y/ScholzHDRLabeled2.jpg
And here’s an animation of its motion over the last 60 years. It’s the star moving in the center of the image:
http://h.dropcanvas.com/vrq2y/scholzanimationfullresolution.gif
It gets suddenly brighter in the last frame because my image consisted of red+infrared light whereas the others used in the animation were red light alone.
