You must have missed HS chemistry too. Boyle’s Law relates Volume and Pressure, not Temperature.
You want Guy Lussac’s Law.
P1/T1 = P2/T2
P1*T2/T1 = P2
filled to minimum pressure at 70 degrees F, how much pressure loss do you get going down to 45 degrees? Remember that the formula is in Kelvin, not Fahrenheit
P2 = 12.5 * 280 / 295 = 11.9 psi.
Therefore, Brady, the Pats and the democrats on this forum who love them are being willfully ignorant on the issue that the temperature would have caused a 2 psi drop in the balls. It would not have. They cheated before the balls hit the field.
The pressure isnt 12.5, it’s 27.2 at sea level...so your answer is about half what it should be.
The football pressure isnt 12.5, it’s 27.2 (14.7 + 12.5) at sea level...so your delta is about half what it should be.
NFL balls are to be inflated to 12.5 - 13.5 psi.
therefore, a 2 psi loss could be 11.5 psi when measured after the game while assuming the highest possible number prior to game (but without having measured it)
playing within the rules, they could fill their balls to 12.5 psi in a 90F room and then take them out to the 40F game. what would be the change?
P1 = 12.5 psi
T1 = 90F == 305K
T2 = 40F == 277K
therefore:
P2 = P1 * T2 / T1
P2 = (12.5) * (277) / (305)
P2 = 11.35 psi