[Pikachu_Dad]

You would have to. Gravity will not be mocked.

At 1,000 fps bullet takes 3 seconds to reach target.

Bullet begins to drop as soon as it leaves the muzzle.

Rate is 9.8 m/s2

So first second is 9.8 meters drop. About 10 yards

[kjam22]

I assume the 3rd second has a much greater drop than the first second....

[Pikachu_Dad]

Initial drop 0 m/s
At 1sec, dropping at 9.8 m/s
At 2 sec, dropping at 19.6 m/s
At 3 sec, dropping at 28.4 m/s

Acceleration is constant at 9.8 m/s2

[HangnJudge]

about 2.5 sec delay from shot to target

d = 1/2 at^2
a = 32 f/sec^2

hm... about 80 foot drop by my guesstimating

80/1000 = .125
about 7 deg up angle
sin(7deg) = .12

[dr_lew]

Rate is 9.8 m/s2

So first second is 9.8 meters drop. About 10 yards

It does not follow. AVERAGE rate is 4.9 m/sec, since it starts at 0 and increases to 9.8 m/sec at the end of 1 sec.

Hence drop is 4.9 meters, or 1/2 a t² as justified by this heuristic.

[editor-surveyor]

>> “Bullet begins to drop as soon as it leaves the muzzle.” <<

.
Not if it is aimed upward on a ballistic trajectory.

What do you think the “elevation” settings on a sight or scope are for?

A projectile aimed upward continues upward for a considerable distance. Brush up on your trigonometry, and ballistics.
.

[ModelBreaker]

It wouldn’t be going 1000 fps the whole way. So it would be quite a bit more than 3 seconds. And quite a bit more than 30 meters.