To: Yosemitest
58 posted on
03/01/2014 7:22:09 AM PST by
Errant
(Surround yourself with intelligent and industrious people who help and support each other.)
To: Errant
The distance of Comet 209P/Linear's orbit to where the Surface of Earth WILL BE in its orbital plane on May 24, 2014 at 00:00:00 ~ isfrom 863,222.98 miles to 863,243.98 miles on the nearest side,and from 871,116.98 miles to 871,158.98 miles to the opposite side of Earth's orbital plane.
Those numbers decrease my concern level considerably from the
"about 18,600 miles" that I commented on in
comment #56.
That's a lot further out than John Bochanski's article stating
" Detailed calculations of its orbit indicated that in May 2014 the comets debris trails would pass extremely close to Earth(about 0.0002 Earth-Sun distances, ...). "
which figured to be about 18,600 miles.
I didn't get it from JPL's models, but I run
Stellarium 0.12.4 for Earth's distance from the Sun on
May 24, 2014 at 00:00:00 Central Daylight Savings Time as 1.00571510 AU .
It showed Comet 209P/Linear distance from the Sun as it is on the same laditude of Earth's Orbital Plane
on May 20, 2014 at 00:00:00 Central Daylight Savings Time, is 0.99639024 AU.
1.00571510 AU minus
0.99639024 AU equals
0.00932486 AU times (Earth is a distance of 0.36184615 AU from Comet Linear at that time)
93,000,000 miles equals
867,211.98 miles from Earth's Orbital Plane
minus the radius of Earth ( 3,9473,968 mi )
59 posted on
03/01/2014 4:28:47 PM PST by
Yosemitest
(It's Simple ! Fight, ... or Die !)
To: Errant
" Perhaps 'm' stands for micron (was that a big M or a little m? :-) "
The only thing in
his paper that addressed it was above the Figure 3 and Figure 4 charts where it stated
It stated below Figure 4
So I used the Logarithm numbers above that statement at the bottom of that chart,
ranging from "-5.0" through "-1.0",
to figure the sizes from
their stated model radius size of Comet 209P/Linear.
60 posted on
03/01/2014 4:45:46 PM PST by
Yosemitest
(It's Simple ! Fight, ... or Die !)
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