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To: spunkets
So you argue that while the 2 is to the right of the divisor is 1/2, but the 9+3 term that is ALSO to the right of the divisor is NOT in fact 1/12.

Stay away from my checkbook please.

629 posted on 04/14/2011 10:38:50 AM PDT by Dead Corpse (explosive bolts, ten thousand volts at a million miles an hour)
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To: Dead Corpse
"So you argue that while the 2 is to the right of the divisor is 1/2, but the 9+3 term that is ALSO to the right of the divisor is NOT in fact 1/12."

That's correct. An operator only operates on one number, or value. It does not operate on multiple numbers, or values, unless indicted to do so explicitly with brackets, or parenthesis. If htose brackets and parenthesis do not appear in the original equaiton, then they do not exist and should never be imagined.

638 posted on 04/14/2011 10:58:57 AM PDT by spunkets
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