To: gorush
At 32 ft/sec2 at the end of the first second the object will have fallen 32 feet. Do you agree? ... And if not, why not?
90 posted on
05/03/2009 6:50:49 PM PDT by
MHGinTN
(Believing they cannot be deceived, they cannot be convinced when they are deceived.)
To: MHGinTN
I disagree. The rate of acceleration is 32’/sec/sec. or 32’/sec. squared. That works out to 16’ in the first second, 46’ in the second second, 76’ in the third second. As an expert rated skydiver I have studied the phenomenon.
91 posted on
05/03/2009 6:56:26 PM PDT by
gorush
(History repeats itself because human nature is static)
To: MHGinTN
In a vacuum that is 16’ in the first second, 48” in the second second and 82’ in the third second.
94 posted on
05/03/2009 7:03:29 PM PDT by
gorush
(History repeats itself because human nature is static)
To: MHGinTN
An easier way to think about it...32’/sec/sec is the speed at the end of the first second...but at the start of the first second we were traveling 0’/sec...we average those out and end up 16’ below the starting point.
96 posted on
05/03/2009 7:07:10 PM PDT by
gorush
(History repeats itself because human nature is static)
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