To: DownWithGreenspan
A quick run through the numbers shows the most glarely fact, and that is registered R's outnumber registered D's by a wopping 20 percent or there abouts. Assuming there is equal turnout for both parties of about 50 percent, then the D's would have to overcome an approximately 22,000 vote edge to the R's. Assuming the D's overcome this disadvantage and all other things being equal, this amounts to about 5 percent of all votes cast being fraudulent!
The only other explanation would be if two thirds of all the other voters went with the D's.
To: truth defector
It is difficult to get enough fraud to beat a 3% legitimate lead statewide:
Not impossible by any means in a small state (where 3% is less than a single precint/region in a couple of big cities where fraud is deliberately ignored...)
Getting enough crooked poll officials in enough precints seems to be the limiting factor: enough fake voters/repeat voters/illegal voters/"highly encouraged" absentee voters (through union intimidation, old-folks home recruitment, hospital "voting", welfare and food kitchen polling/registration means crooked democratic voters are ALWAYS available.
But if the numbers are more than 5% fraud has always been ignored in the past.
Then again, the national press corpse ignored democractic vote fraud in any event.
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