He states that the ejected object traveled at 3200 feet in about 7 seconds, yet he states the speed as 1500 feet/sec. That's obviously wrong. He also neglects to convert the weight of the missle body from pounds to the unit of mass in the foot-pound-second system, which is a slug.
So the velocity should be;
v = 3200/7 = 457 feet/sec
The equation for kinetic energy is;
E = (m * v2)/2, where;
E = Energy (foot pounds)
m = mass (slugs)
v = velocity (feet/sec)
A slug = 32.17 pounds, so we'll add that to the equation to convert from pounds to slugs..
E = (m * v2)/64.34
Solving for E, we have;
E = (15 * 4572)/64.34 = 48,690 foot pounds
I'd say that value would ALSO suggest a missile, as its energy is still extremely high..
As the muzzle energy of a .50 BMG rifle round is a little over 12,000 foot pounds, I'd say that 48,690 foot pounds is A LOT of energy. In comparison, a .308 rifle bullet has a muzzle energy of about 2520 foot pounds, and IT can pass through a telephone pole or a tree....