Correct me if I’m wrong.
If it takes 3 seconds to travel the 1.5 miles that bullet will fall many feet due to the force of gravity. The applicable formula is:
S = .5 * g * t *t
Where
g = 32.2 feet per second per second
t = 3 seconds
This gives a total drop of about 58 feet!
Compensate for that sometime you wannabe sharpshooters.
Data
On
Previous
Engagements
D.O.P.E. Invaluable to snipers.
Just like in the old days of black powder.
S = .5 * g ^ (t*t)
At that range, it more resembles a mortar.
I did. That was about the drop for .308 when shooting 1km using a 19” barrel.
Very-long-range shooting pretty-much requires a precision laser rangefinder.
I get more like 144 feet (on a 3 second shot). That’s a fairly substantial amount to compensate for - and stay accurately enough for a throat shot!
; )
Or just plug the numbers into your ballistic computer, or use the equivalent app on your smartphone. A 2000-meter Newcon rangefinder is a pretty handy thing to have along as well.
Range 3 at Camp Atterbury in Indiana will be among the base range facilities open in August for the National Long-Range service rifle championships in August. The range offers targets a mile distant, and black rifles made of aluminum and plastic have not yet come to dominate the activities there. I'll be giving it a try with a M98 Mauser in the original 7,92x57mm caliber, but using Hornady 196-gr boattail hollowpoints, the same weight as the old German WWI watercooled Maxim heavy machinegun load used for 2000-2500 meter arcing fire in the days of trench-to-trench shooting across no man's land.
I'm dropping a little over 50 inches at 500 meters, the longest range I have to work with on short notice. Which seems to work about right, as calculated by your formula.