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The miss distance was holding steady at about 30,000 kilometers, or 18,600 miles.

.. damn.. just damn.

1 posted on 01/09/2008 3:32:04 PM PST by NormsRevenge
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Near-Earth Object Program: http://neo.jpl.nasa.gov


2 posted on 01/09/2008 3:32:20 PM PST by NormsRevenge (Semper Fi ... Godspeed ... ICE’s toll-free tip hotline —1-866-DHS-2-ICE ... 9/11 .. Never FoRGeT)
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To: NormsRevenge

Dang! Now we have to wait another 1000 years. :(


3 posted on 01/09/2008 4:29:50 PM PST by Does so (...against all enemies, DOMESTIC and foreign...)
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To: NormsRevenge
The size of a football field, the asteroid could blast a half-mile-wide crater into the Martian surface.

Too bad.

I was really hoping for a massive impact..

4 posted on 01/09/2008 4:32:50 PM PST by dragnet2
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To: NormsRevenge

The path is as calculated, the error radius decreasing with each passing day. The asteroid will miss, which is disappointing since much would be learned about Mars from a fresh crater 1000 feet deep.


6 posted on 01/09/2008 4:35:20 PM PST by RightWhale (Dean Koonz is good, but my favorite authors are Dun and Bradstreet)
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To: NormsRevenge

There’s a paradox here. Model this like a dart game with Mars about 8.8 Martian radii away from the bulls eye. Suppose the “dart” has an expected Gaussian distribution along two axes in the plane of the dart board ( The plane normal to the path of the asteroid which contains Mars )

Working in units of Martian radii, Mars covers an area of pi on the board, so the probability of hitting Mars is just pi times N(sigma,8.8), where N is the 2-d Normal Distribution as a function of r, the distance from the bulls eye. Note that N(sigma,r) gives the probability per unit area of hitting at a distance r.

So, using my handy dandy homemade yacc implemented calculator in cygwin, I evaluate pi*N(sigma,8.8) for different values of sigma, and find that sigma = 6.8 gives a value of 0.025 for the probability of hitting Mars. The paradox is ( if I’m doing it right ) that the asteroid has only about a 50% chance of passing within 8.8 Martian radii of the target point. That is, within the circle around the bullseye drawn at the distance of Mars. Intuitively, you would tend to think that this would mean a much higher chance of hitting Mars than 2.5% .

Another way of putting it is that the Normal probability distribution centered at 8.8 Martian radii which gives a probability of 0.025 for hitting Mars is much more diffuse than you would expect.


9 posted on 01/09/2008 10:00:34 PM PST by dr_lew
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To: NormsRevenge

So, if it’s not going to hit Mars, where is it going to go?


10 posted on 01/17/2008 9:11:11 PM PST by Shadowstrike (Be polite, Be professional, but have a plan to kill everyone you meet.)
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