Psst. 205 squared divided by 170 squared = 1.45
Secondly, its not a matter of KE but rather power vs drag.
Oops! Must've Oh well, it amounts to probably another 67 horsepower (45 percent of 150). Not likely without a turbo or nitrous.
Yeah 77 percent more would've been 226 MPH.
square root of ((170x170)x 1.77)= 226
I looked at the video-- he appeared to be in sixth gear at about 11,100 rpm. I think we could figure out his real speed based on gear ratios, provided of course his sprockets and gearing are stock.
drag = Cd x R x V(squared)/2 x A
Cd = coeff. of drag
R = density
V = velocity
A = area
??? Absolutely it's a matter of power vs. drag, and as you can see from the drag equation (second one), the power required to equal the drag at any given speed is proportional to the square of the velocity.
Put another way, the kinetic energy is not much of a factor-- if the Hayabusa weighed 2,000 pounds, the horsepower requirement would be the same because the frontal form factor would still be the same, so the top speed would be-- the same! The kinetic energy at the same top speed would be much higher (also a function of the square of the velocity), but that only means the bike would take longer to achieve the speed. (Assuming the tires would take the extra weight, discounting the additional friction, etc.)