>> Tell ya what, here's a simple set of arithmetic identities, all valid in finite math, and an equivalent set could easily be part of a useful program. tell me what c resolves to and provide the proof of your answer.
a = b + 1
b = a - 1
c = b + 1
<<
Unlees I'm missing something This appears to just be a linear relationship (i.e. a straight line) a=b+1 where a and c are interchangable. Am I missing something?
The line would be 45 degrees with intercepts of (0,1) and (-1,0)
The system could be reduced to 2 lines a=b+1 and A=c
I guess I've got to be missing something.
I asked you to resolve c, not to solve the equations. I will recast the problem in a more classic form so as to avoid this interpretation:
b = 1 a = f1(b) - 1 f1(b) = f1(a) + 1 solve for a, providing a proof of your answerPlease note that I can write a useful program that looks exactly like this--so there's no traction in claiming that it doesn't really exist.