[Hardcorps]

How do you solve this one? A man and his wife, together their ages are 98..he is twice the age that she was when he was the age she is today. How old is he and how old is his wife? This problem drove me crazy in a high school logic class many years ago. You are supposed to solve it using reason and logic only. Yep I do know the answer.

[supercat]

How do you solve this one?

Start by factoring 98. >:*3

[watchin]

He's 56 ... she's 42

[watchin]

You start with visualizing something like this:

Her ............Her/Him ........... Him

Since his age "now" is double that of hers "then", and the difference between "then" and "now" is the same as the diffence in their ages ...

He is twice as old as "double the difference in their ages", or four times as old as "the difference in their ages."

The difference in their ages must be an even number, in order for the sum of their ages to add up to the even number 98.

[fnord]

3a = 4b

a = man's age
b = woman's age
algebra
solve for a + b = 98

[hashangayasri]

both are 49 aren’t they //