To: OXENinFLA
The 7.62 calibre round from his L96 sniper rifle curved 56ft in the air before striking its target in the chest, killing him instantly 56 feet at 900 yards? The must mean "inches".
6 posted on
04/06/2003 10:15:03 AM PDT by
Mulder
(It's all for nothing if you don't have Freedom)
To: Mulder
got to be inches.
To: Mulder
http://www.biggameinfo.com/BalCalc.aspx At 800 Yds.:
In a 50 MPH cross wind the bullet will move laterally 35.9 Ft
The bullet's drop from the muzzle if fired level with the ground would be 85.1 Ft.
The elevation correction from a nominal "zero" of 500 yards would be 15.8 Ft.
Play with the calculator in the link using different assumptions. The output is given in inches and clicks
57 posted on
04/06/2003 1:20:37 PM PDT by
Calamari
To: Mulder
56 feet at 900 yards? The must mean "inches". You have to be right. That is a very hard shot, but he would have to be using a crossbow to get 56 feet of windage.
So9
63 posted on
04/06/2003 2:45:01 PM PDT by
Servant of the Nine
(We are the Hegemon. We can do anything we damned well please.)
To: Mulder
Definitely not inches. And 56 feet is wrong too. The drop at that range should be no more than approximately 20 feet. Must be an error on the reporters part.
Either way, if the story is true, that was one lucky shot. Combining wind drift and drop into a one shot kill at that range takes alot of skill, and a whole lot more luck.
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson