Ok folks. Math in the morning.
First, complete the square for:
x[squared] + bx
Then, in a different problem, solve for x in:
ax[squared] + bx + c = 0. a, b, and c not equal to 0.
Show all work for both problems.
Nice way to ruin a beautiful morning.
I could do that.
During the Nixon Administration.
X equals negative b plus or minus the square root of b squared minus four times a times c over two times a.