Sort of. According to GreenPapers.com, Idaho has a 20% threshold to be awarded any delegates. They also have a rule that if any candidate wins more than 50% of the delegates (not 50% of the popular vote) then they win all of the delegates.
So right now, only two candidates have more than 20% of the vote in Idaho. That means that as of right now, Cruz is winning more than 50% of the delegates. If that is the way the night ends, Trump gets no delegates from Idaho. That would mean that after winning Michigan and Mississippi, Trump would have fewer delegates than Cruz for the night, even before the voting in Hawaii.
Ironically enough, Trump's only hope to come out of tonight with the most delegates is to root for Rubio to break 20% in Idaho.
I hope you are right. God bless Idaho.
Interesting information.. thanks.
Not so, it’s a majority of the popular votes.
“Finally, Idaho also has a true winner-take-all trigger as well. Should one candidate win a majority of the vote statewide, that candidate would also be entitled to all of the delegates from the state. This may or may not be likely in a less crowded field. The last two winners in Idaho received more than 50% of the vote.”
http://frontloading.blogspot.com/2016/01/2016-republican-delegate-allocation_25.html