[ROCKLOBSTER]

Remember that if you take a right angle (a) from a storm's path, it's closest point to you, when it passes, will lie at the intersection of your path and its own (A; plot your line in the other direction). But if you're driving at an angle (b) that keeps you ahead of the storm's path while heading away from it, when that storm reaches point A, you're still ahead of the storm and can still drive further before it reaches closest point of approach B.

Of course in real life, you'd have to be real lucky and find a road that veers off at the correct angle for any of that to apply.

Out there, in some of those state, they have a county dirt road matrix that surrounds the sections (square miles) so you could zig zag.

[Styria]

Of course in real life, you'd have to be real lucky and find a road that veers off at the correct angle for any of that to apply.

Out there, in some of those state, they have a county dirt road matrix that surrounds the sections (square miles) so you could zig zag.

I know that's the big limit for applying the maneuvering board to land, but tornados usually don't run parallel to the roads either where you take off at a right angle. I just wanted to show how you'd solve it geometrically.