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To: catfish1957
On a direct curved trajectory, she got the inherent force of the bullet (diminished by air viscosity forces) but added by a vertical drop component regained after dropping from the top of it. A "drop only" energy or force of work into her head would be much smaller, but from a 50 slug still significant. A hail storm of that size is painful, let alone of that mass or density. I dunno, if people can hit and kill animals with long barreled muzzle loaders at these distances, it still is possible, I guess, to kill someone that way by accident, imo. Heavy bullets have inherent higher inertia and thus are less prone to energy dissipation than lighter bullet. It has to do with Reynolds' number of a ball of lead. Check the ration of Inertia to air viscosity... http://www.grc.nasa.gov/WWW/BGH/reynolds.html The higher the density and linear density of the bullet the more energy it keeps. An arrow is light but has great length and thus comparatively large linear density and could be deadly when merely dropped, and so may be a large calliber bullet compared to a pellet size one. And also the following http://slinging.org/wiki/index.php?title=Reynolds_Number&redirect=no "" Reynolds Number From Slinging.org Wiki The Reynolds number is one of the main variables used in sling ballistics calculations. As a general rule, if two bullets have the same shape and Reynolds number, they will show the same aerodynamic behavior, even if they have different sizes or move with different velocities. Therefore, ballistic tables and formulas are greatly simplified when put in terms of the Reynolds number. Another advantage of the Reynolds number is that it is dimensionless, that is, its value is independent of the unit system used to measure it. The formula for the Reynolds number is: where is the air density, η is the air's viscosity, v is the velocity of the projectile, and D is the characteristic lenght of the bullet. Conventions for Reynolds number determination.The characteristic length of the bullet is computed as follows: since most sling bullets are bodies of revolution, they posses an axis of rotation, which is generally called the principal chord line of the bullet (see image to the right). The characteristic length of the bullet is simply the length of the segment that results from intersecting the bullet with its principal chord line. Therefore, the characteristic length for a sphere is its diameter, for a cylinder its length, and so on. ""
146 posted on 12/20/2011 11:51:09 AM PST by JudgemAll (Democrats Fed. job-security Whorocracy & hate:hypocrites must be gay like us or be tested/crucified)
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To: JudgemAll

Sorry...I only made a B in College Physics :)


187 posted on 12/20/2011 2:29:14 PM PST by catfish1957 (Save a Pretzel for the Gas Jets!!!)
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