Can you tell us how to solve this one?
Alice traveled by bus at an average speed of 20 miles per hour. Then she traveled by moped at an average speed of 44 miles per hour. In total, she traveled 216 miles for 6 hours. How many minutes did Alice travel by moped? (Round to the nearest minute.)
r*t = d
rate times time = distance
20X = distance traveled by bus 44Y = distance traveled by moped
X+Y = 6 20X + 44Y = 216
Y = 6-x
Substitute in second equation
20X + 44(6-X) = 216 20X + 264-44X = 216
-22X = -48
X = 48/22 = 24/11 = 2 2/11 hours or approx 131 minutes Y = 6-X, Y = 6 - 2 2/11 = 3 9/11 hours or approx 229 minutes
Answer: Time moped is 4 hours
Solution
Dm + Db= 216
Distance = rateXtime
Distance of the bus + Distance of the moped= 216
( rate of bus)( time of bus) + ( rate of moped)( time of moped) = 216
20(time of bus)+ 44( time of moped)+ 216
Time of moped + time of bus = 6 hours
Time of moped= (6) -(time of bus)
20( time of bus) + 44 {(6)- (time of bus)}= 216
20 (tb )+ 264- 44( tb) =21 6
264 - 24(tb) = 216
-24( tb) =21 6 - 264
- 24( tb)= -48
time of bus = 2 hours
time of moped= 4 hours
Oops! They wanted minutes
4 x 60= 240 minutes
I just read this post to my husband. He quipped, “Who would ride for 6 hours with a bathroom break?”
“Can you tell us how to solve this one?
Alice traveled by bus at an average speed of 20 miles per hour. Then she traveled by moped at an average speed of 44 miles per hour. In total, she traveled 216 miles for 6 hours. How many minutes did Alice travel by moped? (Round to the nearest minute.)”
Geeze, that was one sporty Moped! I was lucky to get much over 25 MPH out of the ones that I owned way back in my past.