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To: Hoodat

There’s 4 variables.

Concentration X, Concentration Y, Crystal Z and Crystal W

Adding concentration X to Z and W gives me two equations:

X+Z -> XZ
X+W -> XW

Adding concentration Y to Z and W gives me two more equations:

Y+Z -> YZ
Y+W -> YW.

I can then use the systems of equations to solve for all 4 variables, once I know the concentration of acid required to dissolve YW and YW. To keep it easier, I make sure I have the exact same amount of both Z and W, and I keep the concentration in the standard solution the same. The only thing that will change between the two is the volume of the acid.


138 posted on 12/16/2010 3:28:29 PM PST by BenKenobi
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To: BenKenobi

How did you standardize the acid solutions (i.e. how do you know what their molarities are)?


139 posted on 12/16/2010 3:37:27 PM PST by Hoodat (Yet in all these things we are more than conquerors through Him who loved us. - (Rom 8:37))
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To: BenKenobi
Let me try again. Let's suppose your standard acid solution is 1.0 M HCl(aq). How would you go about preparing that standard 1.0 M solution?
142 posted on 12/16/2010 3:46:51 PM PST by Hoodat (Yet in all these things we are more than conquerors through Him who loved us. - (Rom 8:37))
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