[Cooter]

Unless the car was launched at an angle, the horizontal speed of the car is not relevant to the vertical distance it fell.

The formula to use is d = 0.5 * g * t^2.
Solving for t would give sqrt(600 ft * 2 / 32 ft/sec^2)= 6.1 seconds.

In those 6.1 seconds the car would travel (6 sec) * (40 mi/hr) * (5280 ft/mi) / (3600 sec/hr) = 358 ft away from the canyon wall, assuming the canyon wall was vertical and the horizontal speed of the car remained constant.

[bill1952]

Heh. Good job there.

Back to my original post, think of those last seconds during the final plunge!