To: beebuster2000
Sorry, but a set cannot contain itself.
10 posted on
06/24/2008 5:32:27 PM PDT by
Panzerlied
("We shall never surrender!")
To: Panzerlied
To: Panzerlied
Sorry, but a set cannot contain itself.
I do not believe that statement is true.
For instance, the set of all sets with at least one member would have to contain itself as a member.
(As an aside: It would, however, have excluded John Wayne Bobbitt for a period of time...but now contains him once again).
102 posted on
06/24/2008 9:02:20 PM PDT by
NonLinear
(When seconds count, the police are only minutes away.)
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