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To: AFreeBird

Don’t think so.

36.5 mi/sec x (60 sec/min) x (60 min/hr) = 131,400 mi/hr????


14 posted on 04/10/2007 5:24:53 AM PDT by mund1011
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To: mund1011; nomodem
LOL, wow did I screw up a calc or what. Thanks for catching that.

I probably shouldn't try math calculations until I've had my morning coffee.

19 posted on 04/10/2007 5:53:40 AM PDT by AFreeBird (This space for rent. Inquire within)
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To: mund1011
Don’t think so.

36.5 mi/sec x (60 sec/min) x (60 min/hr) = 131,400 mi/hr????

That warp drive they salvaged from the Roswell crash site makes a great overdrive.

But even Eugen Sänger's WWII Silbervogal design was to have hit a top speed of 22,100 km/h (13,800 mph) following a climb to an altitude of 145 km/ 90 miles. After which it would then gradually descend into the stratosphere, where the increasing air density would generate lift against the flat underside of the aircraft, eventually causing it to "bounce" and gain altitude again, where this pattern would be repeated. Because of drag, each bounce would be shallower than the preceding one, but it was still calculated that the Silbervogel would be able to cross the Atlantic, deliver an 4,000 kg/8,800 pound bomb to the continental US, and then continue its flight to a landing site somewhere in the Japanese held Pacific, a total journey of 24,000 km/15,000 miles.


26 posted on 04/11/2007 6:30:50 AM PDT by archy (Et Thybrim multo spumantem sanguine cerno. [from Virgil's *Aeneid*.])
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