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To: LibWhacker
“Afshar’s experiment consists of the clever idea of putting small absorbing wires at the exact position of the dark interference fringes, where you expect no light,” Knoesel said. “He then observed that the wires do not change the total light intensity, so there are really dark fringes at the position of the wires. That proves that light also behaves as a wave in the same experiment in which it behaves as a particle.”

I don't get it. I stand in the sun, and my body casts a shadow, and my hand's shadow disappears when I move it into my trunk shadow. Are these learned Solons saying that my hand shadow can still be discerned in some way?

11 posted on 03/12/2007 11:44:52 PM PDT by brityank (The more I learn about the Constitution, the more I realise this Government is UNconstitutional !!)
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To: brityank

The dark area of an interference fringe is not a "shadow", to begin with. That's where waves of light cancel off each other. Or something to that effect.


12 posted on 03/13/2007 12:05:21 AM PDT by CarrotAndStick (The articles posted by me needn't necessarily reflect my opinion.)
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To: brityank

I believe they mean that when light acts as a particle, it should hit the shadow area, but it does not and indvidualy goes through either hole. Thus the photon chooses one hole or the other for some strange reason, and instead of light acting as a wave interference in the shadow area, it's more of a logical like switching that occurs, according to a certain clock.

This could have fantastic repercution in nano-computer development and "artificial intelligence" as it is more akin to the transistor effect. It also would mean there is no uncertainty...


14 posted on 03/13/2007 12:33:30 AM PDT by JudgemAll (Condemn me, make me naked and kill me, or be silent for ever on my gun ownership and law enforcement)
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